Programming Challenge 5.22 - Square Display

/* Square Display - This program asks the user for a positive integer no
   greater than 15. The program then displays a square on the screen using
   the character 'X'. The number entered by the user will be the length of
   each side of the square.
  
   Example:
  
   If the user enters 5, the program displays:
  
   XXXXX
   XXXXX
   XXXXX
   XXXXX
   XXXXX
  
   If the user enters 8, the program displays:

   XXXXXXXX
   XXXXXXXX
   XXXXXXXX
   XXXXXXXX
   XXXXXXXX
   XXXXXXXX
   XXXXXXXX
   XXXXXXXX */

#include "Utility.h"

int main()
{
    /* Constant: Minimum number of 'X' characters,
       Maximum number of 'X' characters */
    const int CHARACTERS_MIN = 2,
              CHARACTERS_MAX = 15;

    /* Variables: Pattern character */
    char pattern = 'X';

    /* Variables: Pattern length, Number of rows (counter variable),
       Number of columns (counter variable) */
    int patternLength = 0,
        numRows,
        numColumns;

    /* Display: Information */
    cout << "\t\tSQUARE DISPLAY\n\n"
         << "Please enter the number of squares for the pattern to\n"
         << "display. ( " << CHARACTERS_MIN
         << " is the lowest, " << CHARACTERS_MAX << " the highest).\n"
         << "Once done, press enter, and enjoy the created pattern.\n\n";    cout << "Number of squares: ";
    cin >> patternLength;

    /* While loop::Input Validation: If the number entered by the user
       is less than CHARACTERS_MIN, or greater than CHARACTERS_MAX, this
       statement will be executed */
    while (patternLength < CHARACTERS_MIN || patternLength > CHARACTERS_MAX)
    {
        /* Display: Error message */
        cout << "\nSorry, it seems that the number entered by you was\n"
             << "either below " << CHARACTERS_MIN
             << " or greater than " << CHARACTERS_MAX << ". Please try again.\n";

        /* Ask again */
        cout << "Number of squares: ";
        cin >> patternLength;
    }

    cout << endl;

    /* For loop: As long as number of rows is smaller than pattern length,
       this loop will iterate */
    for (numRows = 0; numRows < patternLength; numRows++)
    {
        /* Nested For loop: As long as the number of columns is smaller
           than pattern length, this loop will iterate */
        for (numColumns = 0; numColumns < patternLength; numColumns++)
        {       
            /* Display: pattern */
            cout << pattern;
        }
        cout << endl;
    }

    pauseSystem();
    return 0;
}